0.7m-0.1m^2=0.5

Solution for 0.7m-0.1m^2=0.5 equation:

0.7m-0.1m^2=0.5

We move all terms to the left:

0.7m-0.1m^2-(0.5)=0

We add all the numbers together, and all the variables

-0.1m^2+0.7m-0.5=0

a = -0.1; b = 0.7; c = -0.5;
Δ = b2-4ac
Δ = 0.72-4·(-0.1)·(-0.5)
Δ = 0.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.7)-\sqrt{0.29}}{2*-0.1}=\frac{-0.7-\sqrt{0.29}}{-0.2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.7)+\sqrt{0.29}}{2*-0.1}=\frac{-0.7+\sqrt{0.29}}{-0.2}
$